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Simplify: ๐‘Ž^โˆ’1/4 โ‹… ๐‘Ž^7/8/6โˆš๐‘Ž^3 - Mathematics

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Question

Simplify:

`(a^((-1)/4) * a^(7/8))/(root(6)(a^3))`

Simplify
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Solution

Given,

`(a^((-1)/4) * a^(7/8))/(root(6)(a^3))`

We have to simplify the given expression.

Thus, `(a^((-1)/4) * a^(7/8))/(root(6)(a^3))`  ...[∴ xn × xm = xn + m]

⇒ `a^((-1)/4 + 7/8)/((a^3)^(1/6)`  ...`[∴ root(n)(x) = x^(1/n)]`

⇒ `a^(((-1)/4 xx 2/2) + 7/8)/((a)^(3 xx 1/6)`

⇒ `(a^((-2)/8 + 7/8))/(a)^(1/2)`

⇒ `a^(5/8)/a^(1/2)`  ...`[∴ x^n/x^m = x^(n - m)]`

⇒ `a^(5/8 - 1/2)`

⇒ `a^(5/8 - (1/2 xx 4/4)) = a^(5/8 - 4/8) = a^(1/8)`

Hence, `(a^((-1)/4) * a^(7/8))/(root(6)(a^3)) = a^(1/8)`.

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Chapter 6: Indices - EXERCISE 6 [Page 66]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 2. (vii) | Page 66
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