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Show that the square of an odd positive integer can be of the form 6q + 1 or 6q + 3 for some integer q.

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Question

Show that the square of an odd positive integer can be of the form 6q + 1 or 6q + 3 for some integer q.

Sum
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Solution

Given: Let n be an odd positive integer. Any odd integer is of the form 6t + 1, 6t + 3 or 6t + 5 for some integer t.

Case 1: n = 6t + 1n2

= (6t + 1)2 

= 36t2 + 12t + 1 

= 6(6t2 + 2t) + 1, so n2 is of the form 6q + 1.

Case 2: n = 6t + 3n2

= (6t + 3)2 

= 36t2 + 36t + 9

= 6(6t2 + 6t + 1) + 3, so n2 is of the form 6q + 3.

Case 3: n = 6t + 5n2

= (6t + 5)2 

= 36t2 + 60t + 25 

= 6(6t2 + 10t + 4) + 1, so n2 is of the form 6q + 1.

From the three possible residue classes for an odd integer modulo 6, its square is either of the form 6q + 1 or 6q + 3.

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Chapter 1: Real Numbers - EXERCISE 1.1 [Page 1.9]

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R.D. Sharma Mathematics [English] Class 10
Chapter 1 Real Numbers
EXERCISE 1.1 | Q 11. | Page 1.9
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