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Show That: Sin 42° Sec 48° + Cos 42° Cosec 48° = 2

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Question

Show that: sin 42° sec 48° + cos 42° cosec 48° = 2.

Sum
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Solution

L.H.S.
= sin 42° sec 48° + cos 42° cosec 48°

= `sin (90° - 48°) xx (1)/(cos 48°) + cos (90° - 48°) xx (1)/(sin 48°)`

= `cos 48° xx (1)/(cos 48°) + sin 48° xx (1)/(sin 48°)`

= 1 + 1
= 2
= R.H.S.

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Chapter 21: Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals] - EXERCISE 21 (F) [Page 334]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 21 Trigonometrical Ratios [Sine, Consine, Tangent of an Angle and their Reciprocals]
EXERCISE 21 (F) | Q 4. (ii) | Page 334
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