English

Show that the kinetic energy of the particle moving in a magnetic field remains constant. - Physics

Advertisements
Advertisements

Question

Show that the kinetic energy of the particle moving in a magnetic field remains constant.

Advertisements

Solution

When a charged particle having charge q moves inside a magnetic field `vecB` with velocity v, it experiences a force `vecF =q(vecV ×vecB)`.

From the formula of the force we can see that, `vecF`is always perpendicular to both `vecV` and `vecB`, thus in this case work done by the force is always zero. From, the work energy theorem we know that the change in the kinetic energy of the body is equal to the work done.

Change in kinetic energy = 0
⇒Kinetic energy = A constant

shaalaa.com
Force on a Moving Charge in Uniform Magnetic and Electric Fields
  Is there an error in this question or solution?
2016-2017 (March) Delhi Set 3

RELATED QUESTIONS

A moving charged particle q travelling along the positive x-axis enters a uniform magnetic field B.
When will the force acting on q be maximum?


A proton and an α-particle move perpendicular to a magnetic field. Find the ratio of radii of circular paths described by them when both have (i) equal velocities, and (ii) equal kinetic energy. 


A flexible wire of irregular shape, abcd, as shown in the figure, turns into a circular shape when placed in a region of magnetic field which is directed normal to the plane of the loop away from the reader. Predict the direction of the induced current in the wire.


Write the expression for Lorentz magnetic force on a particle of charge ‘q’ moving with velocity `vecv` in a magnetic field`vecB`. Show that no work is done by this force on the charged particle.


An electric current i enters and leaves a uniform circular wire of radius a through diametrically opposite points. A charged particle q, moving along the axis of the circular wire, passes through its centre at speed v. The magnetic force acting on the particle, when it passes through the centre, has a magnitude equal to


A 10 g bullet with a charge of 4.00 μC is fired at a speed of 270 m s−1 in a horizontal direction. A vertical magnetic field of 500 µT exists in the space. Find the deflection of the bullet due to the magnetic field as it travels through 100 m. Make appropriate approximations.


A proton describes a circle of radius 1 cm in a magnetic field of strength 0.10 T. What would be the radius of the circle described by an α-particle moving with the same speed in the same magnetic field?


A narrow beam of singly-charged carbon ions, moving at a constant velocity of 6.0 × 104m s−1, is sent perpendicularly in a rectangular region of uniform magnetic field B = 0.5 T (figure). It is found that two beams emerge from the field in the backward direction, the separations from the incident beam being 3.0 cm and 3.5 cm. Identify the isotopes present in the ion beam. Take the mass of an ion = A(1.6 × 10−27) kg, where A is the mass number.


A uniform magnetic field of 1.5 T exists in a cylindrical region of radius 10.0 cm, its direction parallel to the axis along east to west. A wire carrying current of 7.0 A in the north to south direction passes through this region. What is the magnitude and direction of the force on the wire if,

(a) the wire intersects the axis,

(b) the wire is turned from N-S to northeast-northwest direction,

(c) the wire in the N-S direction is lowered from the axis by a distance of 6.0 cm?


Current flows through uniform, square frames as shown in the figure. In which case is the magnetic field at the centre of the frame not zero?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×