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Show that cos(2tan-1 17)=sin(4tan-1 13) - Mathematics

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Question

Show that `cos(2tan^-1  1/7) = sin(4tan^-1  1/3)`

Sum
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Solution

L.H.S. `cos(2tan^-1  1/7)`

= `cos[cos^-1  (1 - 1/49)/(1 + 1/49)]`  .....`[because 2tan^-1x = cos^-1  (1 - x^2)/(1 + x^2)]`

= `cos[cos^-1  48/50]`

= `cos[cos^-1  24/25]`

= `24/25`

R.H.S `sin[4 tan^-1  1/3]`

= `sin[2tan^-1 ((2 xx 1/3)/(1 - 1/9))]` .....`[because 2tan^-1x = tan^-1  (2x)/(1 - x^2)]`

= `sin[2tan^-1  ((2/3)/(8/9))]`

= `sin[2tan^-1  3/4]`

= `sin[sin^-1  (2 xx 3/4)/(1 + 9/16)]`  ......`[because 2tan^-1x = sin^-1  (2x)/(1 + x^2)]`

= `sin[sin^-1  24/25]`

⇒ `24/25`

L.H.S. = R.H.S.

Hence poved.

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Chapter 2: Inverse Trigonometric Functions - Exercise [Page 36]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Exercise | Q 10 | Page 36

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