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Show graphically that the system of equations x – 2y = 5, 3x – 6y = 15 has infinitely many solutions.

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Questions

Show graphically that the system of equations x – 2y = 5, 3x – 6y = 15 has infinitely many solutions.

Show graphically that the following given system of equations has infinitely many solutions:

x – 2y = 5, 3x – 6y = 15

Graph
Sum
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Solution

From the first equation, write y in terms of x 

`y = (x - 5)/2`   ...(i)

Substitute different values of x in (i) to get different values of y

For x = –5, y = `(-5 - 5)/2` = –5

For x = 1, y = `(1 - 5)/2` = –2

For x = 3, y = `(3 - 5)/2` = –1

Thus, the table for the first equation (x – 2y = 5) is

x –5 1 3
y –5 –2 –1

Now, plot the points A(–5, –5), B(1, –2) and C(3, –1) on a graph paper and join A, B and C to get the graph of x – 2y = 5.

From the second equation, write y in terms of x

`y = (3x - 15)/6`   ...(ii)

Now, substitute different values of x in (ii) to get different values of y

For x = –3, y = `(-9 - 15 )/6` = –4

For x = –1, y = `(-3 - 15)/6` = –3

For x = 5, y = `(15 - 15)/6` = 0

So, the table for the second equation (3x – 6y = 15) is

x –3 –1 5
y –4 –3 0

Now, plot the points D(–3, –4), E(–1, –3) and F(5, 0) on the same graph paper and join D, E and F to get the graph of 3x – 6y = 15.


From the graph, it is clear that, the given lines coincide with each other.

Hence, the solution of the given system of equations has infinitely many solutions.

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Chapter 3: Linear Equations in Two Variables - EXERCISE 3A [Page 94]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 3 Linear Equations in Two Variables
EXERCISE 3A | Q 25. | Page 94
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