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Shilpa has a 4 year recurring deposit account in Bank of Maharashtra and deposits Rs 800 per month. If she gets Rs 48200 at the time of maturity, find i. the rate of simple interest. - Mathematics

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Question

Shilpa has a 4 year recurring deposit account in Bank of Maharashtra and deposits Rs 800 per month. If she gets Rs 48200 at the time of maturity, find

  1. the rate of simple interest.
  2. the total interest earned by Shilpa.
Sum
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Solution

Deposit per month (P) = Rs 800

Amount of maturity = Rs 48200

Period (n) = 4 years = 48 months

Let rate of interest be R% p.a.

Total principal for one month

= `(P(n)(n + 1))/(2)`

= `(800 xx 48 xx (48 + 1))/(2)`

= `₹(800 xx 48 xx 49)/(2)`

= ₹ 940800

Total deposit:

= ₹ 800 × 48

= ₹ 38400

and amount of maturity

= ₹ 48200

∴ Interest earned

= ₹ 48200 − ₹ 38400

= ₹ 9800

(i) Rate of interest

= `("S.I" xx 100)/("P" xx "T")`

= `(9800 xx 100 xx 12)/(940800)`

= 12.5%
(ii) Total interest earned by Shilpa

= ₹ 9800

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Chapter 2: Banking - Chapter Test

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Nootan Mathematics [English] Class 10 ICSE
Chapter 2 Banking
Exercise 2A | Q 14. | Page 23

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