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Ankita started paying Rs 400 per month in a 3 years recurring deposit. After six months her brother Anshul started paying Rs 500 per month in a 2 1 2 years recurring deposit. The bank paid 10% p.a

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Question

Ankita started paying Rs 400 per month in a 3 years recurring deposit. After six months her brother Anshul started paying Rs 500 per month in a `2(1)/(2)` years recurring deposit. The bank paid 10% p.a. simple interest for both. At maturity who will get more money and by how much?

Sum
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Solution

In case of Ankita,

Deposit per month = Rs 400

Period (n) = 3 years = 36 months

Rate of interest = 10%

Total principal for one month

= `400 xx ("n"("n" + 1))/(2)`

= `400 xx (36(36 + 1))/(2)`

= `₹(400 xx 36 xx 37)/(2)`

= ₹ 266400

Interest

= `"prt"/(100)`

= `(266400 xx 10 xx 1)/(100 xx 12)`

= ₹ 2220

∴ Amount of maturity

= ₹ 400 × 36 + ₹ 2220

= ₹ 14400 + ₹ 2220 

= ₹ 16620

In case of Anshul,

Deposit P.m. = ₹ 500

Rate of interest = 10%

Period (n) = `2(1)/(2)` year = 30months

∴ Total principal for one month

= `₹500 xx ("n"("n" + 1))/(2)`

= `500 xx (30(30 + 1))/(2)`

= `₹(500 xx 30 xx 31)/(2)`

= ₹ 232500

Interest

= `(232500 xx 10 xx 1)/(100 xx 12)`

= ₹ 1937.50

Amount of maturity

= ₹ 500 × 30 + ₹ 1937.50

= ₹ 15000 + ₹ 1937.50 

= ₹ 16937.50

At maturity Anshul will get more amount

DIfference

= ₹ 16937.50 - ₹ 16620.00

= ₹ 317.50.

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Chapter 2: Banking - Chapter Test [Page 25]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 2 Banking
Chapter Test | Q 6. | Page 25

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