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Question
Set up an equation in the following case:
In an isosceles triangle, the vertex angle is twice either base angle. (Let the base angle be b in degrees. Remember that the sum of angles of a triangle is 180 degrees.)
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Solution
An isosceles triangle has two of its angles of equal measure.
Let base angle be b.
Vertex angle = 2 × Base angle = 2b
Sum of all interior angles of a Δ = 180°
b + b + 2b = 180°
4b = 180°
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