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Question
Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car ( with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m with
base dimensions 4 m × 3m?
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Solution
Given that
Shelter length = 4m
Breadth = 3m
Height = 2.5m
The tarpaulin will be required for four sides of the shelter
Area of tarpaulin in required`=2(lb+bh+hl)`
`=[2(4)xx2.5+(3xx2.5)+4xx3]m^2`
`=[2(10+7.5)+12]m^2`
`47m^2=47m^2`
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