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Rationalise the denominator of the following: 7 − 4⁢√3/7 + 4⁢√3 - Mathematics

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Question

Rationalise the denominator of the following:

`(7 - 4sqrt(3))/(7 + 4sqrt(3))`

Sum
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Solution

Given expression: `(7 - 4sqrt(3))/(7 + 4sqrt(3))`

Step 1: To rationalise the denominator, multiply the numerator and denominator by the conjugate of the denominator `7 - 4sqrt(3)`:

`(7 - 4sqrt(3))/(7 + 4sqrt(3)) xx (7 - 4sqrt(3))/(7 - 4sqrt(3))`

= `(7 - 4sqrt(3))^2/((7)^2 - (4sqrt(3))^2`

Step 2: Calculate the denominator:

`7^2 - (4sqrt(3))^2`

= 49 – 16 × 3

= 49 – 48

= 1

Step 3: Expand the numerator: 

`(7 - 4sqrt(3))^2`

= `7^2 - 2 xx 7 xx 4sqrt(3) + (4sqrt(3))^2`

= `49 - 56sqrt(3) + 16 xx 3`

= `49 - 56sqrt(3) + 48`

= `97 - 56sqrt(3)`

Step 4: So the expression becomes:

`(97 - 56sqrt(3))/1 = 97 - 56sqrt(3)`

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Chapter 1: Rational and Irrational Numbers - Exercise 1E [Page 32]

APPEARS IN

Nootan Mathematics [English] Class 9 ICSE
Chapter 1 Rational and Irrational Numbers
Exercise 1E | Q 2. (i) | Page 32
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