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Rate constant for the reaction 2NA2OA5⟶4NOA2+OA2 is 4.98 × 10–4 s–1. Find the order of reaction?

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Question

Rate constant for the reaction \[\ce{2N2O5 -> 4NO2 + O2}\] is 4.98 × 10–4 s–1. Find the order of reaction?

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Solution

Since the unit of rate constant is s–1, the reaction is first order.

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Chapter 6: Chemical Kinetics - Very short answer questions

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SCERT Maharashtra Chemistry [English] 12 Standard HSC
Chapter 6 Chemical Kinetics
Very short answer questions | Q 4

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