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Prove the following: sin2(-160∘)sin270∘+sin(180∘-θ)sinθ = sec220° - Mathematics and Statistics

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Question

Prove the following:

`(sin^2(-160^circ))/(sin^(2)70^circ) + sin(180^circ - theta)/sintheta` = sec220°

Sum
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Solution

sin(– 160°) = – sin 160°

= – sin(180° – 20°)

= – sin 20°

sin 70° = sin (90° – 20°) = cos 20°

∴ L.H.S. = `(sin^2(-160^circ))/(sin^(2)70^circ) + sin(180^circ - theta)/sintheta`

= `((-sin20^circ)^2)/((cos20^circ)^2) + sintheta/sintheta`

= `(sin^(2)20^circ)/(cos^(2)20^circ) + 1`

= 1 + tan220°

= sec220°

= R.H.S.

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Trigonometric Functions of Triple Angle
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Chapter 3: Trigonometry - 2 - Exercise 3.3 [Page 48]

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