Advertisements
Advertisements
Question
Prove the following identities:
`1/(1 - sinA) + 1/(1 + sinA) = 2sec^2A`
Advertisements
Solution
L.H.S. = `1/(1 - sinA) + 1/(1 + sinA)`
= `(1 + sinA + 1 - sinA)/((1 - sinA)(1 + sinA))`
= `2/(1 - sin^2A)`
= `2/cos^2A`
= 2 sec2 A = R.H.S.
RELATED QUESTIONS
Prove that:
`(tanA + 1/cosA)^2 + (tanA - 1/cosA)^2 = 2((1 + sin^2A)/(1 - sin^2A))`
Prove that:
(1 + tan A . tan B)2 + (tan A – tan B)2 = sec2 A sec2 B
`1+ (cot^2 theta)/((1+ cosec theta))= cosec theta`
What is the value of 9cot2 θ − 9cosec2 θ?
If sin θ + sin2 θ = 1, then cos2 θ + cos4 θ =
Prove the following identity :
`(1 + cotA + tanA)(sinA - cosA) = secA/(cosec^2A) - (cosecA)/sec^2A`
Find the value of ( sin2 33° + sin2 57°).
Prove that `(tan^2 theta - 1)/(tan^2 theta + 1)` = 1 – 2 cos2θ
Choose the correct alternative:
cos 45° = ?
Show that: `tan "A"/(1 + tan^2 "A")^2 + cot "A"/(1 + cot^2 "A")^2 = sin"A" xx cos"A"`
