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Question
Prove the following identities:
`(1 - sin θ)/(1 + sin θ) = (sec θ - tan θ)^2`
Theorem
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Solution
RHS = `(1/(cos θ) - (sin θ)/(cos θ))^2`
= `(1 - sin θ)^2/(cos^2θ)`
= `(1 - sin θ)^2/((1 - sin^2θ))`
= `((1 - sin θ))/((1 + sin θ))` = LHS
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