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Question
Prove that the sum of nth term from the beginning and nth term from the end of an A.P. is constant.
Sum
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Solution
a = first term,
d = common difference,
l = last term.
Using the formula,
an = a + (n − 1)d
nth term from end = l − (n − 1)d
[a + (n − 1)d] + [l − (n − 1)d]
= a + l
The sum is a + l, which is independent of n.
The sum of the nth term from the beginning and the nth term from the end of an A.P. is constant.
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