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Question
Prove that the line through (0, 0) and (2, 3) is parallel to the line through (2, −2) and (6, 4).
Sum
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Solution
⇒ The first line passes through points (0, 0) and (2, 3),
Using the slope formula:
`m = (y_2 - y_1)/(x_2 - x_1)`
`m_1 = (3 - 0)/(2 - 0)`
∴ `m_1 = 3/2`
⇒ The second line passes through points (2, −2) and (6, 4),
Using the slope formula:
`m = (y_2 - y_1)/(x_2 - x_1)`
`m_2 = (4 - (-2))/(6 - 2)`
`m_2 = (4 + 2)/4`
`m_2 = 6/4`
∴ `m_2 = 3/2`
Since the slopes of both lines are equal `(m_1 = m_2 = 3/2)`, the line passing through (0, 0) and (2, 3) is parallel to the line passing through (2, −2) and (6, 4).
Hence Proved.
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