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`Prove the Following Trigonometric Identities. `(Sec a - Tan A)^2 = (1 - Sin A)/(1 + Sin A) - Mathematics

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Question

`Prove the following trigonometric identities.

`(sec A - tan A)^2 = (1 - sin A)/(1 +  sin A)`

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Solution

We need to prove  `(sec A - tan A)^2  = (1 - sin A)/(1 +  sin A)`

Here, we will first solve the L.H.S.

Now using `sec theta = 1/cos theta` and `tan theta = sin theta/cos theta` we get

`(sec A - tan A)^2 = (1/cos A - sin A/cos A)^2`

`= ((1 -sin A)/cos A)^2`

`= (1 - sin A)^2/(cos A)^2`

Further using the property  `sin^2 theta + cos^2 theta = 1` we get

`((1 - sin A)^2/(cos A)) = (1 - sin A)^2/(1 - sin^2 A)`

`= (1 - sin A)^2/((1 - sin A)(1 + sin A))`            (using `a^2 - b^2 = (a + b)(a - b))`

`= (1 - sin A)/(1 +  sin A)`

henc e proved

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Chapter 11: Trigonometric Identities - Exercise 11.1 [Page 45]

APPEARS IN

RD Sharma Mathematics [English] Class 10
Chapter 11 Trigonometric Identities
Exercise 11.1 | Q 39 | Page 45

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