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Prove the Following Sin θ Sin (90° − θ) − Cos θ Cos (90° − θ) = 0

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Question

Prove the following:

sin θ sin (90° − θ) − cos θ cos (90° − θ) = 0

Theorem
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Solution

We have to prove sin θ sin (90° − θ) − cos θ cos (90° − θ) = 0

Left-hand side

`= sin theta.sin(90^@ - theta) - cos theta.cos(90^@ - theta)`

`=  sin theta.cos theta - cos thete.sin theta`

`= sin theta (cos theta -cos theta)`

= 0

=Right hand side

Proved

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Chapter 10: Trigonometric Ratios - EXERCISE 10.3 [Page 10.37]

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R.D. Sharma Mathematics [English] Class 10
Chapter 10 Trigonometric Ratios
EXERCISE 10.3 | Q 7. (i) | Page 10.37
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