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Question
Prove following:
(a' + b') . (a' + b) . (a + b') = a' . b'
Theorem
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Solution
Using: (x + y)(x + z) = x + yz
LHS = (a′ + b′)(a′ + b)(a + b′)
= [a′ + b′ b](a + b′)
= (a′ + 0)(a + b′)
= a′(a + b′)
= a′ a + a′b′
= 0 + a′b′
= a′b′
LHS = RHS
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