Question

Propanoic acid to ethylamine.

Answer 1

\[\ce{\underset{\text{Propanoic acid}}{CH_3CH_2COOH} + NH_3 -> CH_3 CH_2COONH_4 ->[{Δ}][{-H_2O}] CH_3 CH_2CONH_2 ->[{Br_2+4NaOH}][{Δ}]\underset{\text{Ethyl amine}}{CH_3CH_2NH_2}+ {Na_2 CO_3} + {2NaBr +2H_2 O}}\]