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Question
Pressure in a water pipe on the ground floor of a building is 100,000 Pa. Calculate the pressure in the water pipe on the first floor at a height of 3 m. [Density of water = 1000 kgm−3 ; g = 10 ms−2]
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Solution
Pressure of water at ground floor = P1 = 1,00,000 Pa
Pressure of water at first floor = P2 = ?
Height of first floor = h = 3 m
Density of water = ρ = 1000 kgm−3
Acceleration due to gravity = g = 10 ms−2
Difference in pressure of water at ground floor an first floor
= P1 − P2
Pressure of water due to height (h) = hρg
⇒ P1 – P2 = hρg
1,00,000 – P2 = 3 × 1000 × 10
P2 = 1,00,000 − 30000
P2 = 70000 Pa
∴ Pressure of water in a pipe at the first floor of a building is 70000 Pa.
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