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Question
Premlata deposits ₹ 5,000 in an R.D. account at 8% p.a. rate of interest. How much per month must she deposit to get the same interest when the rate of interest is increased by 2%. Time in both the cases is same.
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Solution
Let the time in both the cases be n months.
In first case:
P = ₹ 5,000, r = 8%
∴ I = `P xx (n(n + 1))/(2 xx 12) xx r/100`
`I_1 = 5,000 xx (n(n + 1))/24 xx 8/100`
In second case:
New rate of interest (r) = 8% + 2%
= 10%
Let new monthly deposit = x
`I_2 = x xx (n(n + 1))/24 xx 10/100`
Since interest is same,
⇒ `5,000 xx (n(n + 1))/24 xx 8/100 = x xx (n(n + 1))/24 xx 10/100`
⇒ `5,000 xx 8/100 = x xx 10/100`
⇒ 5000 × 8 = 10x
⇒ 40000 = 10x
⇒ x = 4000.
Hence, Premlata must deposit ₹ 4,000 per month to get the same interest when the rate of interest is increased by 2%.
