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Pramod is 25 kg heavier than his wife, Pranita. After a dieting course, Pramod loses 20 kg and Pranita loses 15 kg, and their total weight is 140 kg. Find their original weight. - Mathematics

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Question

Pramod is 25 kg heavier than his wife, Pranita. After a dieting course, Pramod loses 20 kg and Pranita loses 15 kg, and their total weight is 140 kg. Find their original weight.

Sum
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Solution

Let the weight of Pranita = x kg,

Then, the weight of Pramod = x + 25 kg.

So, after dieting:

Pramod’s weight = (x + 25) − 20 = x + 5

Pranita’s weight = x − 15

According to the problem, their total weight after dieting is 140 kg.

(x + 5) + (x − 15) = 140

2x − 10 = 140

2x = 150

x = `150/2`

∴ x = 75

So,

Pranita’s weight = 75

Pramod’s weight = 75 + 25 = 100kg

Hence, Pranita’s original weight = 75 kg, and Pramod’s original weight = 100 kg

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Chapter 5: Simultaneous Linear Equations - MISCELLANEOUS EXERCISE [Page 62]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 5 Simultaneous Linear Equations
MISCELLANEOUS EXERCISE | Q 9. | Page 62
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