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Question
P(−5, 7), A(3, k) and B(k, −1) are given points. If PA = PB, find the value of k.
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Solution
Given:
Points P(−5, 7), A(3, k), and B(k, −)
Condition: PA = PB
Calculate the distance PA using the distance formula between points
P(−5, 7) and A(3, k):
\[PA = \sqrt{(3 − (−5))^2 + (k − 7)^2}\]
= \[\sqrt{(3+5)^2 + (k − 7)^2}\]
= \[\sqrt{8^2 + (k − 7)^2}\]
= \[\sqrt{64 + (k − 7)^2}\]
Calculate the distance PB using the distance formula between points
P(-5, 7) and B(k, -1):
\[PB = \sqrt{(k - (-5))^2 + (-1 - 7)^2}\]
= \[\sqrt{(k + 5)^2 + (-8)^2}\]
= \[\sqrt{(k + 5)^2 + 64}\]
\[\sqrt{64 + (k - 7)^2}\] ...[Since PA = PB, we equate the distances.]
= \[\sqrt{(k + 5)^2 + 64}\]
64 + (k − 7)2 = (k + 5)2 + 64 ...[Square both sides to eliminate the square root]
\[(k - 7)^2 = (k + 5)^2\] ...[Subtract 64 from both sides]
(k − 7)2 = k2 − 14k + 49
(k + 5)2 = k2 + 10k + 25 ...[Expand both sides]
k2 − 14k + 49 = k2 + 10k + 25
−14k + 49 = 10k + 25 ...[Subtract k2 from both sides]
−14k − 10k = 25 − 49 ... [Rearranging terms]
− 24k = −24
−14k − 10k = 25 − 49
−24 = k = 1 ...[Divide both sides by]
