Question

On the equatorial line of a dipole (θ = 90°), the electric potential is:

Options

• Negative

• Zero

• \[\frac{p}{4\pi\varepsilon_0 r^2}\]

• Undefined

Answer 1

On the equatorial line, θ = 90°, so \[\cos(90°) = 0\]. Therefore, \[V = \frac{p \times 0}{4\pi\varepsilon_0 r^2} = 0\]. The equatorial line is an equipotential surface at zero potential, despite the electric field being non-zero there.