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Obtain the relationship between ΔH and ΔU for gas phase reactions.

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Questions

Obtain the relationship between ΔH and ΔU for gas phase reactions.

Derive the relation between ΔH and ΔU for a gaseous phase reaction.

Derivation
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Solution

At constant pressure, ΔH and ΔU are related as,

ΔH = ΔU + PΔV    ...(1)

For reactions involving gases, ΔV cannot be neglected.

Therefore, ΔH = ΔU + PΔV

= ΔU + P(V2 – V1)

= ΔU + PV2 – PV1    ...(2)

Where V1 is the volume of gas-phase reactants, and V2 is that of the gaseous products.

We assume the reactant and product behave ideally. Applying the ideal gas equation, PV = nRT. Suppose that n1 moles of gaseous reactants produce n2 moles of gaseous products. Then,

PV1 = n1RT and PV2 = n2RT    ...(3)

Substitution of equation (3) into equation (2) yields:

ΔH = ΔU + n2RT – n1RT

= ΔU + (n2 – n1) RT

= ΔU + Δng RT    ...(4)

Where, Δng is the difference between the number of moles of products and those of reactants.

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Chapter 4: Chemical Thermodynamics - Exercises [Page 88]

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