Question

Obtain the minterm canonical form of the Boolean expression by algebraic method.

xyz + xy + x'(yz' + y'z)

Answer 1

F​ = xyz + xy + x′yz′ + x′y′z

   = xyz + xy(z + z′) + x′yz′ + x′y′z

   = xyz + xyz + xyz′ + x′yz′ + x′y′z

   = x′y′z + x′yz′ + xyz′ + xyz​

Therefore,

F = Σm(1, 2, 6, 7)