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Obtain an expression for the torque acting on a rotating body with constant angular acceleration. Hence state the dimensions and SI unit of torque.

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Questions

Obtain an expression for the torque acting on a rotating body with constant angular acceleration. Hence state the dimensions and SI unit of torque.

Obtain an expression for the torque acting on a rotating body with constant angular acceleration.

Sum
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Solution

For m1, a1 = r1α

For m2, a2 = r2α

For mn, an = rnα

f1 = m1a1 = m1r1α

f2 = m2a2 = m2r2α

fn = mnrnα

Torque `(vectau) = vecr xx vecf`

= rfsin90°

τ = rf

`tau_1 = "r""f"_1 = "m"_1"r"_1^2alpha`

`tau_2 = "m"_2"r"_2^2alpha`

`tau_"n" = "m"_"n""r"_"n"^2alpha`

`tau = tau_1 + tau_2 + ... + tau_n`

Total Torgue on  the body, `vectau_"net" = vectau_1 + vectau_2 + vectau_3 + ... vectau_"n"`

= `"m"_1"r"_1^2alpha + "m"_2"r"_2^2alpha + ..... +  "m"_"n""r"_"n"^2alpha`

= `alpha("m"_1"r"_1^2 + "m"_2"r"_2^2 + ..... +  "m"_"n""r"_"n"^2)`

I = mr2

`vectau_"net" = ("I"_1 + "I"_2 + "I"_3 + ......"I"_n)alpha`

= `"I"alpha`

Unit: N.m

dimension: [ML2T-2]

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Chapter 1: Rotational Dynamics - Short Answer II

APPEARS IN

SCERT Maharashtra Physics [English] Standard 12 Maharashtra State Board
Chapter 1 Rotational Dynamics
Short Answer II | Q 2
Balbharati Physics [English] Standard 12 Maharashtra State Board
Chapter 1 Rotational Dynamics
Exercises | Q 8 | Page 24

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