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Question
O is the centre of the circle. CD is a side of a regular octagon. ∠COD = 45°, AB is a side of a regular pentagon. Find ∠AOB.
Options
60°
80°
72°
40°
MCQ
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Solution
72°
Explanation:
Step 1:
A regular pentagon has n = 5 sides.
Step 2:
The angle ∠AOB is given by `360^circ/n`
`∠AOB = 360^circ/5`
Step 3:
∠AOB = 72°
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