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O is centre of the circle and ∠AOC = 120°. Statement (1): ∠ABC = 120° Statement (2): ∠ABC + ∠ADC = 180°⇒ ∠ABC + 60° = 180°

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Question

O is centre of the circle and ∠AOC = 120°.

A circle with centre O, points A, B, and C on the circumference, and central angle AOC marked 120°.

A cyclic quadrilateral with centre O and central angle AOC marked 120°.

Statement (1): ∠ABC = 120°

Statement (2): ∠ABC + ∠ADC = 180°
⇒ ∠ABC + 60° = 180°

Options

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

MCQ
Assertion and Reasoning
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Solution

Both the statements are true.

Explanation:

Since, the angle, which an arc of a circle subtends at the center of the circle is double the angle which it subtends at any point on the remaining part of the circumference.

⇒ ∠AOC = 2 × ∠ADC

⇒ 120° = 2 × ∠ADC

⇒ ∠ADC = `(120°)/2`​ = 60°

ABCD form a cyclic quadrilateral and sum of opposite angles of cyclic quadrilateral is 180°.

⇒ ∠ADC + ∠ABC = 180°

⇒ 60° + ∠ABC = 180°

⇒ ∠ABC = 180° − 60°

⇒ ∠ABC = 120°

So, both statement are true.

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Chapter 17: Circles - TEST YOURSELF [Page 273]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 17 Circles
TEST YOURSELF | Q 1. (n) | Page 273
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