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Question
Numerical Problems.
An iron ball requires 1000 J of heat to raise its temperature by 20°C. Calculate the heat capacity of the ball.
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Solution
Heat capacity C’ = `"Q"/"ΔT"`
Here, A = 1000 J
T = 20°C – 0°C = 20°C = 20 k
C= `1000/20` = 50 JK-1
Here, A = 1000 J
T = 20°C – 0°C = 20°C = 20 k
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