English

Number of molecules in 0.49 g of H2SO4 is ______ × 10^21.

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Question

Number of molecules in 0.49 g of H2SO4 is ______ × 1021.

Options

  • 6.022

  • 30.11

  • 0.03

  • 3.01

MCQ
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Solution

Number of molecules in 0.49 g of H2SO4 is 3.01 × 1021.

Explanation:

Moles of H2SO4​ = `0.49/98` = 0.005

Number of molecules = 0.005 × 6.022 × 1023

= 3.011 × 1021

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Notes

As per the Lakhmir Singh textbook, the question is written (“number of atoms”), the answer should be 21.08 × 1021, which is not among the options.

Therefore, if the textbook gives (d) 3.01, it is actually calculating the number of H2SO4 molecules, not the total number of atoms.

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Chapter 5: Mole Concept and Stoichiometry - Intext Question [Page 101]

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Lakhmir Singh Chemistry [English] Class 10 ICSE
Chapter 5 Mole Concept and Stoichiometry
Intext Question | Q 3. (iii) | Page 101
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