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Question
Net capacitance of three identical capacitors in series is 2 μF. What will be their net capacitance if connected in parallel?
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Solution
When connected in series, the net capacitance is 2 μF.
z`=>1/C +1/C+1/C =1/2`
`=> C = 6muF`
When connected in parallel,
Ceq = C1 + C2 + C3 = 6 μF + 6 μF + 6 μF = 18 μF.
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