Question

Net capacitance of three identical capacitors in series is 2 μF. What will be their net capacitance if connected in parallel?

Answer 1

When connected in series, the net capacitance is 2 μF.

z`=>1/C +1/C+1/C =1/2`

`=> C = 6muF`

When connected in parallel,

C_eq = C₁ + C₂ + C₃ = 6 μF + 6 μF + 6 μF = 18 μF.