Advertisements
Advertisements
Question
Multiply:
(x2 + y2) by (3a + 2b)
Advertisements
Solution
To multiply, we will use distributive law as follows:
\[\left( x^2 + y^2 \right)\left( 3a + 2b \right)\]
\[ = x^2 \left( 3a + 2b \right) + y^2 \left( 3a + 2b \right)\]
\[ = 3a x^2 + 2b x^2 + 3a y^2 + 2b y^2\]
Thus, the answer is \[3a x^2 + 2b x^2 + 3a y^2 + 2b y^2\].
RELATED QUESTIONS
Find each of the following product:
(−5xy) × (−3x2yz)
Find each of the following product:
(−4x2) × (−6xy2) × (−3yz2)
Simplify: a2(2a − 1) + 3a + a3 − 8
Multiply:
(7x + y) by (x + 5y)
Multiply:
(3x2 + y2) by (2x2 + 3y2)
Multiply:
(3x2y − 5xy2) by \[\left( \frac{1}{5} x^2 + \frac{1}{3} y^2 \right)\].
Find the following product and verify the result for x = − 1, y = − 2:
(x2y − 1) (3 − 2x2y)
Simplify:
(2x2 + 3x − 5)(3x2 − 5x + 4)
Show that: (4pq + 3q)2 − (4pq − 3q)2 = 48pq2
Multiply:
16xy × 18xy
