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Multiply: 4abc − 5a2bc − 6ab2c and − 2abc2

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Question

Multiply:

4abc − 5a2bc − 6ab2c and − 2abc2

Sum
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Solution

4abc − 5a2bc − 6ab2c × − 2abc2

= − 8a2b2c3 + 10a3b2c3 + 12a2b3c3

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Chapter 14: Fundamental Concepts (Including Angles and their Properties) - Exercise 19 (C)

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Selina Concise Mathematics [English] Class 6 ICSE
Chapter 14 Fundamental Concepts (Including Angles and their Properties)
Exercise 19 (C) | Q 8.6
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