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Multiple Choice Question. A hydraulic lift is designed to lift heavy objects of maximum mass 2000 kg. The area of cross-section of piston carrying the load is 2.25 × 10-2 m2. What is the maximum

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Question

Multiple Choice Question.

A hydraulic lift is designed to lift heavy objects of maximum mass 2000 kg. The area of cross-section of piston carrying the load is 2.25 × 10-2 m2. What is the maximum pressure the smaller piston would have to bear?

Options

  • 0.8711 × 106 N/m2

  • 0.5862 × 107 N/m2

  • 0.4869 × 105 N/m2

  • 0.3271 × 104 N/m2

MCQ
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Solution

0.8711 × 106 N/m2

Explanation:

Apply Newton’s second law of motion to find the force:

F = mg

Substitute the value mass as m = 2000 kg and acceleration due to gravity as g = 9.81 m/s2 to find the force exerted by the piston.

F = mg

F = 2000 kg × 9.81 m/s2

F = 19620 N

Use the law of pressure

p = `F/A`

Substitute the value of force as F = 19620 N, and area as A = 2.25 × 10–2m2 to calculate the maximum pressure the hydraulic lift can bear.

Pmax = `(19620N)/(2.25 xx 10^-2m^2)`

Pmax = 0.8711 × 106Pa

 
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Chapter 2: Mechanical Properties of Fluids - Exercises [Page 54]

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Balbharati Physics [English] Standard 12 Maharashtra State Board
Chapter 2 Mechanical Properties of Fluids
Exercises | Q 1.1 | Page 54

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