Question

\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]

0.02 moles of pure MnO₂ is heated strongly with conc. HCl. Calculate moles of salt formed.

Answer 1

1 mole MnO₂ gives = 1 mole of MnCl₂

So, 0.02 mole MnO₂will give = 0.02 mole of MnCl₂