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MnOA2+4HCl⟶MnClA2+2HA2O+ClA2 0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate moles of salt formed. - Chemistry

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प्रश्न

\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]

0.02 moles of pure MnO2 is heated strongly with conc. HCl. Calculate moles of salt formed.

संख्यात्मक
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उत्तर

1 mole MnO2 gives = 1 mole of MnCl2

So, 0.02 mole MnO2will give = 0.02 mole of MnCl2

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