Advertisements
Advertisements
Question
Making use of the cube root table, find the cube root
7800
Advertisements
Solution
We have: \[7800 = 78 \times 100\]
∴ \[\sqrt[3]{7800} = \sqrt[3]{78 \times 100} = \sqrt[3]{78} \times \sqrt[3]{100}\]
By the cube root table, we have: \[\sqrt[3]{78} = 4 . 273 \text{ and } \sqrt[3]{100} = 4 . 642\]
\[\sqrt[3]{7800} = \sqrt[3]{78} \times \sqrt[3]{100} = 4 . 273 \times 4 . 642 = 19 . 835 (\text{ upto three decimal places} )\]
Thus, the answer is 19.835
APPEARS IN
RELATED QUESTIONS
Find the smallest number by which the following number must be divided to obtain a perfect cube.
135
Prove that if a number is trebled then its cube is 27 times the cube of the given number.
Write the units digit of the cube of each of the following numbers:
31, 109, 388, 833, 4276, 5922, 77774, 44447, 125125125
Write true (T) or false (F) for the following statement:
8640 is not a perfect cube.
Find the cube root of the following integer −32768 .
Show that: \[\sqrt[3]{27} \times \sqrt[3]{64} = \sqrt[3]{27 \times 64}\]
Find the units digit of the cube root of the following number 175616 .
Find the cube-root of -1331
Find the cube-root of 0.000027
The cube root of 8000 is 200.
