Question

Making use of the cube root table, find the cube root
7800

Answer 1

We have: \[7800 = 78 \times 100\]

∴ \[\sqrt[3]{7800} = \sqrt[3]{78 \times 100} = \sqrt[3]{78} \times \sqrt[3]{100}\]

By the cube root table, we have: \[\sqrt[3]{78} = 4 . 273 \text{ and }  \sqrt[3]{100} = 4 . 642\]

\[\sqrt[3]{7800} = \sqrt[3]{78} \times \sqrt[3]{100} = 4 . 273 \times 4 . 642 = 19 . 835 (\text{ upto three decimal places} )\]

Thus, the answer is 19.835