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प्रश्न
Making use of the cube root table, find the cube root
7800
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उत्तर
We have: \[7800 = 78 \times 100\]
∴ \[\sqrt[3]{7800} = \sqrt[3]{78 \times 100} = \sqrt[3]{78} \times \sqrt[3]{100}\]
By the cube root table, we have: \[\sqrt[3]{78} = 4 . 273 \text{ and } \sqrt[3]{100} = 4 . 642\]
\[\sqrt[3]{7800} = \sqrt[3]{78} \times \sqrt[3]{100} = 4 . 273 \times 4 . 642 = 19 . 835 (\text{ upto three decimal places} )\]
Thus, the answer is 19.835
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