Advertisements
Advertisements
Question
Make I the subject of the following M = `"L" /"F"(1/2"N" - "C") xx "I"`. Find I, If M = 44, L = 20, F = 15, N = 50 and C = 13.
Advertisements
Solution
M = `"L" /"F"(1/2"N" - "C") xx "I"`
⇒ M - L = `(1)/"F"(1/2"N" - "C") xx "I"`
⇒ F(M - L) = `(1/2"N" - "C") xx "I"`
⇒ F(M - L) = `(("N" - 2"C")/2) xx "I"`
⇒ `(2"F"("M" - "L"))/(("N" - 2"C")) = "I"`
Substituting the values of M = 44, L = 0, F = 15, N = 50 and C = 30, we get
I = `(2"F"("M" - "L"))/(("N" - 2"C")`
= `(2 xx 15(44 - 20))/(50 - 2 xx 13)`
= `(30 xx 24)/(24)`
= 30.
APPEARS IN
RELATED QUESTIONS
The simple interest on a sum of money is the product of the sum of money, the number of years and the rate percentage. Write the formula to find the simple interest on Rs A for T years at R% per annum.
The volume V, of a cone is equal to one third of π times the cube of the radius. Find a formula for it.
How many minutes are there in x hours, y minutes and z seconds.
Make R the subject of formula A = `"P"(1 + "R"/100)^"N"`
Make r2 the subject of formula `(1)/"R" = (1)/"r"_1 + (1)/"r"_2`
Make a the subject of formula x = `sqrt(("a" + "b")/("a" - "b")`
Given: mx + ny = p and y = ax + b. Find x in terms of m, n, p, a and b.
If A = pr2 and C = 2pr, then express r in terms of A and C.
Make x the subject of the formula y = `(1 - x^2)/(1 + x^2)`. Find x, when y = `(1)/(2)`
"Area A oof a circular ring formed by 2 concentric circles is equal to the product of pie and the difference of the square of the bigger radius R and the square of the bigger radius R and the square of the smaller radius r. Express the above statement as a formula. Make r the subject of the formula and find r, when A = 88 sq cm and R = 8cm.
