Advertisements
Advertisements
Question
Make h the subject of the formula K = `sqrt("hg"/"d"^2 - "a"^2`. Find h, when k = -2, a = -3, d = 8 and g = 32.
Advertisements
Solution
K = `sqrt("hg"/"d"^2 - "a"^2`
Squaring both sides, we get
⇒ K2 = `"hg"/"d"^2 -"a"^2`
⇒ K2 + a2 = `"hg"/"d"^2`
⇒ (K2 + a2)d2 = hg
⇒ h = `(("K"^2 + "a"^2)"d"^2)/"g"`
Substituting k = 2, a = -3, d = 8 and g = 32, we get
h = `(((-2)^2 + (-3)^2) (8)^2)/(32)`
= `((4 + 9)64)/(32)`
= 26.
APPEARS IN
RELATED QUESTIONS
The fahrenheit temperature, F is 32 more than nine -fifths of the centigrade temperature C. Express this relation by a formula.
Make L the subject of formula T = `2pisqrt("L"/"G")`
Make R2 the subject of formula R2 = 4π(R12 - R22)
Make k the subject of formula T = `2pisqrt(("k"^2 + "h"^2)/"hg"`
If A = pr2 and C = 2pr, then express r in terms of A and C.
Make s the subject of the formula v2 = u2 + 2as. Find s when u = 3, a = 2 and v = 5.
Make y the subject of the formula x = `(1 - y^2)/(1 + y^2)`. Find y if x = `(3)/(5)`
Make x the subject of the formula a = `1 - (2"b")/("cx" - "b")`. Find x, when a = 5, b = 12 and
Make c the subject of the formula a = b(1 + ct). Find c, when a = 1100, b = 100 and t = 4.
"Area A oof a circular ring formed by 2 concentric circles is equal to the product of pie and the difference of the square of the bigger radius R and the square of the bigger radius R and the square of the smaller radius r. Express the above statement as a formula. Make r the subject of the formula and find r, when A = 88 sq cm and R = 8cm.
