Advertisements
Advertisements
प्रश्न
Make h the subject of the formula K = `sqrt("hg"/"d"^2 - "a"^2`. Find h, when k = -2, a = -3, d = 8 and g = 32.
Advertisements
उत्तर
K = `sqrt("hg"/"d"^2 - "a"^2`
Squaring both sides, we get
⇒ K2 = `"hg"/"d"^2 -"a"^2`
⇒ K2 + a2 = `"hg"/"d"^2`
⇒ (K2 + a2)d2 = hg
⇒ h = `(("K"^2 + "a"^2)"d"^2)/"g"`
Substituting k = 2, a = -3, d = 8 and g = 32, we get
h = `(((-2)^2 + (-3)^2) (8)^2)/(32)`
= `((4 + 9)64)/(32)`
= 26.
APPEARS IN
संबंधित प्रश्न
The volume V, of a cone is equal to one third of π times the cube of the radius. Find a formula for it.
Make a formula for the statement:"The number of diagonals, d, that can be drawn from one vertex of an n sided polygon to all the other vertices is equal to the number of sides of the polygon less 3"
Make V the subject of formula K = `(1)/(2)"MV"^2`
Make d the subject of formula S = `"n"/(2){2"a" + ("n" - 1)"d"}`
Make R2 the subject of formula R2 = 4π(R12 - R22)
Make c the subject of formula x = `(-"b" ± sqrt("b"^2 - 4"ac"))/(2"a")`
Make f the subject of the formula D = `sqrt((("f" + "p")/("f" - "p"))`. Find f, when D = 13 and P = 21.
"The volume of a cylinder V is equal to the product of π and square of radius r and the height h". Express this statement as a formula. Make r the subject formula. Find r, when V = 44cm3, π = `(22)/(7)`, h = 14cm.
The total energy E possess by a body of Mass 'm', moving with a velocity 'v' at a height 'h' is given by: E = `(1)/(2) "m" "u"^2 + "mgh"`. Find m, if v = 2, g = 10, h = 5 and E = 104.
"Area A oof a circular ring formed by 2 concentric circles is equal to the product of pie and the difference of the square of the bigger radius R and the square of the bigger radius R and the square of the smaller radius r. Express the above statement as a formula. Make r the subject of the formula and find r, when A = 88 sq cm and R = 8cm.
