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∫ Log ( 1 + 1 X ) X ( 1 + X ) D X - Mathematics

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Question

\[\int\frac{\log\left( 1 + \frac{1}{x} \right)}{x \left( 1 + x \right)} dx\]
Sum
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Solution

\[\int\frac{\log \left( 1 + \frac{1}{x} \right)}{x\left( 1 + x \right)}dx\]

\[Let, \log \left( 1 + \frac{1}{x} \right) = t\]

\[ \Rightarrow \frac{1}{1 + \frac{1}{x}} \times \frac{- 1}{x^2} = \frac{dt}{dx}\]

\[ \Rightarrow \left( \frac{x}{x + 1} \right) \times \frac{- 1}{x^2} = \frac{dt}{dx}\]

\[ \Rightarrow \frac{- dx}{x\left( x + 1 \right)} = dt\]

\[ \Rightarrow \frac{dx}{x\left( x + 1 \right)} = - dt\]

\[Now, \int\frac{\log \left( 1 + \frac{1}{x} \right)}{x\left( 1 + x \right)}dx\]

= ∫ t   . (-dt)

\[ = \frac{- t^2}{2} + C\]

\[ = - \frac{1}{2} \left\{ \log\left( 1 + \frac{1}{x} \right) \right\}^2 + C\]

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Chapter 19: Indefinite Integrals - Exercise 19.09 [Page 57]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.09 | Q 2 | Page 57

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