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Ln the given figure, if PB = 20 cm and OA = 15 cm, then find the shortest distance between the circle and P. -

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Question

ln the given figure, if PB = 20 cm and OA = 15 cm, then find the shortest distance between the circle and P.

Options

  • 20 cm

  • 25 cm

  • 15 cm

  • 10 cm

MCQ

Solution

10 cm

Explanation:

Since OA = OB

∴ OB = 15cm

∴ ΔOBP is a right angled triangle.

∴ OB2 + BP2 = OP2

⇒ (15)2 + (20)2 = OP2

⇒ OP2 = 625

⇒ OP = 25 cm

The shortest distance between circle and P is CP.

We know, OC = 15 cm

∴ CP = OP – OC 

= (25 – 15) cm

= 10 cm

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Geometry (Entrance Exam)
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