Question

ln the given figure, if PB = 20 cm and OA = 15 cm, then find the shortest distance between the circle and P.

विकल्प

• 20 cm

• 25 cm

• 15 cm

• 10 cm

Answer 1

10 cm

Explanation:

Since OA = OB

∴ OB = 15cm

∴ ΔOBP is a right angled triangle.

∴ OB² + BP² = OP²

⇒ (15)² + (20)² = OP²

⇒ OP² = 625

⇒ OP = 25 cm

The shortest distance between circle and P is CP.

We know, OC = 15 cm

∴ CP = OP – OC 

= (25 – 15) cm

= 10 cm