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Lim X → 0 Log ( 1 + X ) 3 X − 1 - Mathematics

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Question

\[\lim_{x \to 0} \frac{\log \left( 1 + x \right)}{3^x - 1}\]

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Solution

\[\lim_{x \to 0} \left[ \frac{\log \left( 1 + x \right)}{3^x - 1} \right]\] 

Dividing the numerator and the denominator by x

\[\lim_{x \to 0} \left[ \frac{\log \left( 1 + x \right)}{x \cdot \left( \frac{3^x - 1}{x} \right)} \right] \left[ \because \lim_{x \to 0} \frac{\log \left( 1 + x \right)}{x} = 1 \lim_{x \to 0} \left( \frac{a^x - 1}{x} \right) = \log a \right]\]
\[ = \frac{1}{\log 3}\]

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Chapter 29: Limits - Exercise 29.1 [Page 71]

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RD Sharma Mathematics [English] Class 11
Chapter 29 Limits
Exercise 29.1 | Q 2 | Page 71

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