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Lim X → 0 √ 1 + X − √ 1 − X 2 X - Mathematics

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Question

\[\lim_{x \to 0} \frac{\sqrt{1 + x} - \sqrt{1 - x}}{2x}\]

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Solution

\[\lim_{x \to 0} \left[ \frac{\sqrt{1 + x} - \sqrt{1 - x}}{2x} \right]\] It is of the form\[\frac{0}{0} .\] 

Rationalising the numerator:

\[\lim_{x \to 0} \left[ \frac{\left( \sqrt{1 + x} - \sqrt{1 - x} \right)\left( \sqrt{1 + x} + \sqrt{1 - x} \right)}{2x\left( \sqrt{1 + x} + \sqrt{1 - x} \right)} \right]\] 

\[\lim_{x \to 0} \left[ \frac{\left( 1 + x \right) - \left( 1 - x \right)}{2x\left( \sqrt{1 + x} + \sqrt{1 - x} \right)} \right]\] 

\[\lim_{x \to 0} \left[ \frac{2x}{2x\left( \sqrt{1 + x} + \sqrt{1 - x} \right)} \right]\] 

\[\frac{1}{\sqrt{1 + 0} + \sqrt{1 - 0}}\] 

\[\frac{1}{2}\] 

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Chapter 29: Limits - Exercise 29.4 [Page 28]

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RD Sharma Mathematics [English] Class 11
Chapter 29 Limits
Exercise 29.4 | Q 4 | Page 28

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