Advertisements
Advertisements
Question
Let \[y=\sin^{-1}x\]. What inverse relation is used for implicit differentiation?
Options
\[x=\cos y\]
\[y=\cos x\]
\[x=\sin y\]
\[y=\sin x\]
MCQ
Advertisements
Solution
If \[y=\sin^{-1}x\], then the inverse relation is \[x=\sin y\]. This relation permits implicit differentiation with respect to \[x\].
shaalaa.com
Is there an error in this question or solution?
